问题:
Given an integer array with all positive numbers and no duplicates, find the number of possible combinations that add up to a positive integer target.
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15nums = [1, 2, 3]
target = 4
The possible combination ways are:
(1, 1, 1, 1)
(1, 1, 2)
(1, 2, 1)
(1, 3)
(2, 1, 1)
(2, 2)
(3, 1)
Note that different sequences are counted as different combinations.
Therefore the output is 7.
解答1
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15public class L377 {
public int combinationSum4(int[] nums, int target) {
//这个利用动态规划的思想
int [] dp = new int [target + 1];
dp[0] = 1;
for(int i = 1; i < dp.length; i ++) {
for(int j = 0; j < nums.length; j ++) {
if(i - nums[j] >= 0) {
dp[i] += dp[i - nums[j]];
}
}
}
return dp[target];
}
}